Card(Wizard) - Ext.js中文手册

描述

卡向导：此布局允许使用容器中的XY坐标定位项目。

语法

这里是使用卡向导布局的简单语法

 layout: 'card'

例

下面是一个简单的例子显示卡向导布局的用法

<!DOCTYPE HTML>
<html>
<head>
   <link href="Https://cdnjs.cloudflare.com/ajax/libs/extjs/6.0.0/classic/theme-classic/resources/theme-classic-all.CSS" rel="stylesheet" />
   <script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/extjs/6.0.0/ext-all.js"></script>
   <script type="text/javascript">
      Ext.onReady(function() {
         Ext.create('Ext.panel.Panel', {
            renderTo: Ext.getBody(),
            requires: [
            'Ext.layout.container.Card'],
            layout: 'card',
            width: 600,
            height: 200,
            bodyPadding: 15,
            defaults: {
               border:false
            },
            defaultListenerScope: true,
            bbar: ['->',
            {
               itemId: 'card-prev',
               text: '« Previous',
               handler: 'showPrevious',
               disabled: true
            },{
               itemId: 'card-next',
               text: 'Next »',
               handler: 'showNext'
            }],

            items: [{
               id: 'card0',
               html: '<h2> This is card wizard layout </h2> <p> This is first card </p> <p> Please click the "Next" button to continue... </p>'
            },{
               id: 'card1',
               html: '<p> This is second card </p> <p> Please click the "Next" button for next card and "Previous" button for previous card... </p>'
            },{
               id: 'card2',
               html: '<p> This is final card </p> <p> Please click the "Previous" button for previous card... </p>'
            }],
            
            showNext: function () {
               this.cardPanelNavigation(1);
            },
            
            showPrevious: function (btn) {
               this.cardPanelNavigation(-1);
            },

            cardPanelNavigation: function (incr) {
               var me = this;
               var l = me.getLayout();
               var i = l.activeItem.id.split('card')[1];
               var next = parseInt(i, 10) + incr;
               l.setActiveItem(next);
               me.down('#card-prev').setDisabled(next===0);
               me.down('#card-next').setDisabled(next===2);
            }
         });
      });
   </script>
</head>
<body>
</body>
</html>

这将产生以下结果